{(x+y)(x-y)-(x-y)的2次方+2y(x-y)}除4y
1个回答
[(x+y)(x-y)-(x-y)^2+2y(x-y)]/4y
=[(x-y)(x+y-x+y+2y)]/4y
=[4y(x-y)]/4y
=x-y
相关问题
{(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y
已知2X-Y=10,求[(X的2次方+Y的2次方)-(X-Y)的2次方+2Y(X-Y)]除以4Y的值.
若(x-2y)的2次方 |y 2|=0,则((x-y)的二次方 (y x)(y-x))除于2y=?
[(x的二次方+的y二次方)-(x-y)的二次方+2y(x-y)]除以4,
((x+y)-2(x+y)的2次方-4(x+y))/(x+y)
(8x3次方y2次方)除(4x2次方y)
(x+y)2次方+4(x-y)2次方-4(x2次方-y2次方)
【(x+2y)方-(x+y)(3x-y)-5y方】除以2x
x(x+y)-(x-y)(x+y)-y^2,其中x=(1/4)的2010次方,y=4的2011次方
若x2+y2+5/4=2x+y,求x的y次方+y的x次方