请稍等,并追问一下
(1)
原式=√2/2+√2/2
=√2
(2)
原式=√2/2×1/2-√2/2
=√2/4-√2/2
=-√2/4
(3) =(√2/2)²+√3×√3/2
=1/2+3/2
=2
(4)=（1-√3/2)/(√3/2)+√3/3
=(2-√3)/√3+√3/3
=2√3/3-1+√3/3
=√3-1
(5)
=[(√3/2)²+(1/2)²]×√3
=1×√3
=√3
请稍等,并追问一下
(1)
原式=√2/2+√2/2
=√2
(2)
原式=√2/2×1/2-√2/2
=√2/4-√2/2
=-√2/4
(3) =(√2/2)²+√3×√3/2
=1/2+3/2
=2
(4)=（1-√3/2)/(√3/2)+√3/3
=(2-√3)/√3+√3/3
=2√3/3-1+√3/3
=√3-1
(5)
=[(√3/2)²+(1/2)²]×√3
=1×√3
=√3