求达人解数学(定积分)的题!鞠躬~

1个回答

  • 很有礼貌

    2.

    tan(x/2)

    =sin(x/2)/cos(x/2)

    =(1-cosx)^(1/2)/(1+cosx)^(1/2)

    ={(1-cosx)^(1/2)/(1+cosx)^(1/2)}*

    {(1+cosx)^(1/2)/(1+cosx)^(1/2)}

    =sinx/(1+cosx)

    1+tan(x/2)=(1+sinx+cosx)/(1+cosx)

    ∫(0,pi/2) dx/(1+sinx+cosx)

    = ∫(0,pi/2) (1/2)dx/{(1/2)(1+cosx)(1+tan(x/2))}

    = ∫(0,pi/2) [{sec(x/2)}^2d(x/2)]/[1+tan(x/2)]

    = ∫(0,pi/2) d[tan(x/2]/(1+tan(x/2)]

    =ln (1+tan(x/2)) (x=0,pi/2)

    3.

    ∫x^2 cosx dx =x^2sinx - ∫2xsinxdx (integration by parts)

    = x^2sinx +2xcosx- ∫2cosxdx

    4.

    f= ∫ (0,1) dx/(1-x^2)^(1/2)

    siny=x

    cosydy=dx

    f= ∫ (0,pi/2) cosy dy/(cosy)=y=arsin(x) [x=0,1]

    1.

    f=∫(0,ln5){e^x (e^x-1)^(1/2))/(e^x+3) dx

    y=e^x

    dy=e^x dx

    f= ∫(1,5) {y-1)^(1/2)/ (y+3) dy

    =(1/(2-3))[2(x-1)^(1/2) -4 ∫dx/[(x+3)(x-1)^(1/2) [x=1,5]

    =-{2(x-1)^(1/2)-4arctan[(x-1)/2]} [x=1,5)