√2(1-√2)=?(√32-√72)-(√300+2√48)=?(1-√3)²=?(√54+3分之1倍√27

2个回答

  • √2(1-√2)

    =√2×1-√2×√2

    =√2-2

    (√32-√72)-(√300+2√48)

    =√32-√72-√300-2√48

    =4√2-6√2-10√3-2×4√3

    =-2√2-10√3-8√3

    =-2√2-18√3

    (1-√3)²

    =1²-2×1×√3+√3²

    =1-2√3+3

    =4-2√3

    (√54+1/3×√27)÷√3

    =√54÷√3+1/3×√27÷√3

    =√(54÷3)+1/3×√(27÷3)

    =√18+1/3×√9

    =3√2+1/3×3

    =3√2+1

    (2√3-3)(√2+√3)

    =2√3×√2+2√3×√3-3×√2-3×√3

    =2√(3×2)+2×3-3√2-3√3

    =2√6+6-3√2-3√3

    (2√x-√y)(√x+2√y)

    =2√x×√x+2√x×2√y-√y×√x-√y×2√y

    =2x+4√xy-√xy-2y

    =2x-3√xy-2y

    (2√6-1)(5√2+√3)

    =2√6×5√2+2√6×√3-1×5√2-1×√3

    =10√12+2√18-5√2-√3

    =10×2√3+2×3√2-5√2-√3

    =20√3+6√2-5√2-√3

    =19√3-√2

    (√3-√2)^2006×(√3+√2)^2007 ( ^ 表示乘方)

    =(√3-√2)^2006×(√3+√2)^2006×(√3+√2)

    =[(√3-√2)(√3+√2)]^2006×(√3+√2)

    =(√3²-√2²)^2006×(√3+√2)

    =(3-2)^2006×(√3+√2)

    =1^2006×(√3+√2)

    =√3+√2