Question

一道简单的电路题.

Answer 1

ω=10Z=5+jωL+(10*(1/jωc)/(10+1/jωc)=5+15j+10/(1+j)=10+10jI=Us/Z=10cos10t/(-45º)I1*Z1=I2*Z2=U',U'=I*10/(1+j)-->I1=5(2)^(/12)cos10t/(-90º)I2=5(2)^(/12)cos10t/(0º)