(x+2根号xy+y)÷(根号x+根号y)
1个回答
(x+2√xy+y)÷(√x+√y)
=(√x+√y)²÷(√x+√y)
=√x+√y
相关问题
化简求值:(X×根号X+X×根号y)÷(XY-Y²)-(X+根号XY+Y)÷X×根号X-Y×根号Y,其中X=1
设x>0,y>0,且根号x(根号x+根号y)=3根号y(根号x+5根号y),求代数式2x+根号xy+2y\x-根号xy-
根号x(x+y)÷根号x+y分之xy平方
【(x-y)^3(x^1/2+y^1/2)^-3+3(x根号y-y根号x)】/(x根号x+y根号y)+(2xy根号xy-
{化简} [x+y/(根号x+根号y)]+[2xy/x·根号y+y·根号x]
已知x,y为正数,且根号x(根号x+根号y)=3根号y(根号x+5根号y),求:(2x+根号xy+3y)/(x+根号xy
若x=(根号3)+1,y=(根号3)-1,求x+(根号xy)/[(根号xy)+y]+(根号xy)-y/x-(根号xy)
``(x-2倍根号xy+y)(根号x +根号y)
化简:((根号x-根号y)^3+2x根号x+y根号y)/(x根号x+y根号y)+(3根号xy-3y)/(x-y)
化简:(x-y)除以(根号x+根号y)-(x-2根号xy+y)除以(根号x-根号y)