设这批树苗X棵:
1班分得的棵数=0.3x+100; -----------(1)
2班分得的棵数=0.6x-50; ------------(2)
1班分得的棵数+2班分得的棵数=x; -----------(3)
即:0.3x+100+0.6x-50=x
可得:x=500
设这批树苗X棵:
1班分得的棵数=0.3x+100; -----------(1)
2班分得的棵数=0.6x-50; ------------(2)
1班分得的棵数+2班分得的棵数=x; -----------(3)
即:0.3x+100+0.6x-50=x
可得:x=500