那就应该是:
(0.3x+0.7)/0.6 -(0.2x-0.3)/0.8=1
(3x+7)/6 -(2x-3)/8=1(分子分母同时乘以10)
(3x+7)*8 -(2x-3)*6=48(等式两边同时乘以48)
24x+58 -12x+18=48
12x+76=48
12x=28
x=28/12
x =7/3
那就应该是:
(0.3x+0.7)/0.6 -(0.2x-0.3)/0.8=1
(3x+7)/6 -(2x-3)/8=1(分子分母同时乘以10)
(3x+7)*8 -(2x-3)*6=48(等式两边同时乘以48)
24x+58 -12x+18=48
12x+76=48
12x=28
x=28/12
x =7/3