四边形求面积知道四边长和一个直角

1个回答

  • 1、设四边形ABCD,AB=4.4,BC=8.2,CD=3.8,AD=8.9,这里A和C都可能是90度,选A是直角,

    S△ABD=8.9*4.4/2=19.58,

    BD=9.928

    S△BCD=√(10.964*1.036*7.164*2.764)

    =14.997,

    S四边形ABCD=19.58+14.997=34.577.

    2、设四边形ABCD

    AB=3.37,BC=9.79,CD=3.76,AD=8.55,

    选A是直角,

    S△ABD=3.37*8.55/2=14.4067

    BD=√84.4194=9.1902

    S△BCD=√11.37*2.18*1.58*7.61

    =17.2635

    S四边形ABCD=14.4067+17.2635=31.67

    3、设四边形ABCD

    AB=3.12,BC=7,CD=3.8,AD=7.5,

    仍设A角为90度,

    S△ABD=7.5*3.12/2=11.7

    BD=8.1231,

    S△BCD=√9.061*0.9384*2.0615*6.0615

    =10.3077

    S四边形ABCD=11.7+10.3077=22.01.