x3+2/x2-x+1 + x3-9/x2+2x+

x3+2/x2-x+1 + x3-9/x2+2x+4=2x-1

1个回答

2（x-2)+2=x+1 2（x-2)-3(4x-)=9(1-x) 7（2x-1)-3(4x-1)=4(3x+2)-1
x(2x-1)2-4(x-3)(x2+3x+9)-(9+2x)(9-2x)=0
(3x^2+9x+7)/(x+1)-(2x^2+4x-3)/(x-1)-(x^3+x+1)/(x^2-1)=
(3x^2+9x+7)/(x+1)-(2x^2+4x-3)/(x-1)-(x^3+x+1)/(x^2-1)=
计算：（1）[x−2/x+3•x2−9x2−4]；（2）[3/x−4−24x2−16]；（3）[1/2x−1x+y•(x
(1) 3x^3-2x-1 (2)x^3+6x^2+11x+6 (3)x^4+2x^3-9x^2-2x+8 (4) (x
(2+3x)/(4-9x)-(1+3x)/(2-3x)-2/(3x-2)
(2+3x/4-9x^2)-(1+3x/2-3x)-(2/3x-2)
①(2x-1)2+3(1-2x)=0②2x2=-9x③3m(m-2)=4-2m④﹙2x－3﹚²＝9﹙2x＋3﹚²⑤x²－
9x+6x²-3(x-2/3x²）其中x=-1 (2)1/2(2x-6x-4)-4(-1+x+1/4