1/3x-(1/2x-4y-6z)+3(-2z+2y)
1个回答
1/3x-(1/2x-4y-6z)+3(-2z+2y)
=1/3x-1/2x+4y+6z-6z+6y
=-1/6x+10y
=-1/6×6+10×1
=9
相关问题
2x-y=7 x+y+z=25x+3y+z=2 x-2y+z=-1 3x-4z=4 x+2y+3z=-1x+y-z=6x
x+y-z=6(1) x-3y+2z=1(2) 3x+2y-z=4(3) 求X Y Z 的值
x-2y+z=-1 3x+4y-2z=7 2x+2y-3z=6
(1)3x+4y=15 2y-z=2 x+2z=9 (2) x+y+z=8 2x+3y-z=6 3x-y+z=8 (3)
x+y-z=6,x+3y+2x=1,3x+2y-z=4
1:7x+2y-z=7 2:6x-y+z=7 3:4x+3y+z=9 1:9x+4y+z+10 2:-9X+2y+3z=
解方程组(1){3x+2y+z=7,2x+3y+4z=3,x+4y+6z=1
解下列方程组(1){y=2x-1,2x+3y+z=8,3x+2y=-4(2){x+y+z=6,x-z=2,2x-y+z=
若1/x+2/y+z/3=4,3/x+2/y+1/z=6.则1/x+1/y+1/z=
(1)y=2x-7 6x+3y+2z=2 3x-4z=4 (2) 4x+9y=12 3y-2z=1 7x+5z=19/4