已知M,N,P三点的坐标分别为(-1,0),(3,-1),(1,2),并且向量ME=1/3向量MP,向量NF=1/3向量

2个回答

  • (1)

    ME = 1/3 MP and NF = 1/3NP

    Let O be the origin

    OE = OM + ME

    =(-1,0)+ ME

    =(-1,0) + 1/3MP (ME=1/3MP)

    =(-1,0) + 1/3(MO + OP)

    =(-1,0) + 1/3(-OM + OP)

    =(-1,0) + 1/3[ -(-1,0)+ (1,2) ]

    =(-1/3,2/3)

    i.e E(-1/3,2/3)

    OF = ON + NF

    = (3,-1) + 1/3(NP)

    = (3,-1) + 1/3(-ON+OP)

    = (3,-1) + 1/3[ -(3,-1)+(1,2) ]

    = (3,-1) + (-2/3,1)

    = (7/3,0)

    i.e F(7/3,0)

    (2)

    EF = EO + OF

    = -(-1/3,2/3) + (7/3,0)

    = (8/3,-2/3)

    MN = MO + ON

    = -(-1,0) + (3,-1)

    =(4,-1)

    Ratio of x co-ordinate ,y co-ordinate of EF = (8/3)/(-2/3) = -4

    Ratio of x co-ordinate ,y co-ordinate of MN = 4/-1 = -4

    Therefore MN//EF