题目不是说“使用一段时间后”了嘛.
氢气量变化了呀
p1V=n1RT1
n1=p1V/(RT1)
p2V=n2RT2
n2=p2V/(RT2)
△n=n1-n2=p1V/(RT1)-p2V/(RT2)=30*10^5*0.1/(8.314*290.15)-10*10^5*0.1/(8.314*300.15)=84.29(mol)
△m=168.58(g)
题目不是说“使用一段时间后”了嘛.
氢气量变化了呀
p1V=n1RT1
n1=p1V/(RT1)
p2V=n2RT2
n2=p2V/(RT2)
△n=n1-n2=p1V/(RT1)-p2V/(RT2)=30*10^5*0.1/(8.314*290.15)-10*10^5*0.1/(8.314*300.15)=84.29(mol)
△m=168.58(g)