Question

1.通过中和滴定实验测得,25.00ML未知浓度的H2SO4溶液与23.80ML0.4200MOL/

Answer 1

1.H2SO4 + 2NaOH = Na2SO4+2H2O

1 2

0.025c 0.0238*0.42

2*0.025c=0.0238*0.42

c=0.19992mol/L

m=Mn=98g/mol*0.025L*0.19992mol/L=0.489804g

2.H2SO4 + 2NaOH = Na2SO4+2H2O

1 2

0.5V 0.04*0.5

2*0.5V=0.04*0.5

V=20ml

H2SO4 + 2Zn = Zn2SO4+H2

1 2

0.08*0.5 x

x=2*0.08*0.5=0.08mol

m=Mx=65g/mol*0.08mol=5.2g