Question

logx(x+1)+logx(x+2)=logx6+1

Answer 1

logx(x+1)+logx(x+2)=logx6+1

logx(x+1)+logx(x+2)=logx(6)+logx(x)

logx (x+1)(x+2)=logx (6x)

(x+1)(x+2)=6x

x²+3x+2=6x

x²-3x+2=0

(x-1)(x-2)=0

x=1或x=2

检验 x=1,底数为1,不满足,是增根

所以 x=2