Question

微积分 lim n[√(n^2+2) -√(n^2+1)]

Answer 1

n[√(n^2+2) -√(n^2+1)] = n/[√(n^2+2) +√(n^2+1)] = 1/[√(1+2/n^2) +√(1+1/n^2)] = 1/(1+1) =1/2