Question

y=（x²-2x+3）/（2x-3）函数的值域

Answer 1

x^2-2x+3=2yx-3y

x^2-(2+2y)x+(3+3y)=0

判别式：

4(y+1)^2-12(y+1)≥0

4(y+1)(y-2)≥0

y≥2或y≤-1