∫(1,2)(x∧2-2x-3)/xdx=∫(1,2)xdx-2∫(1,2)dx-3∫(1,2)dx/x=3/2-2-3In2=-1/2-3In2
∫(1,2)(x∧2-2x-3)/xdx
2个回答
相关问题
-
求∫(1,2)(x∧2-2x-3)/xdx
-
∫(1,2)x∧2–2x–3/xdx定积分
-
求四道不定积分填空题的解1.( )xdx=d(x^2)2.( )xdx=d(1-x^2)3.( )sin3/2xdx=d
-
∫xsin2xdx=1/2∫x(-cos2x)′dx=1/2(-xcos2x+∫(x)′cos2xdx)=-x/2cos
-
∫xdx/(1-2x-x^2)RT
-
求个不定积分:I = ∫xdx/√[1+x^2+√(1+x^2)^3]
-
1:∫xdx/(x+1)(x+2)(x+3)=∫[2/x+2-1/2/x+1-3/2/x+3]dx的详细过程!主要是分子
-
不定积分∫sinxcos3xdx=?,∫√x(x2+1)dx=?
-
∫2/x∧2sec∧2 1/xdx
-
求不定积分:∫[(1-x^2)/(1+x^2)]^(1/2)xdx