如图:
Rt△ABE中,∠ABE=60°,AB=40,
∴BE=20m,AE=20
3 m,
设DF=GE=x,CF=y,则AG=20
3 -x,DG=30+y,
则有:
x 2 + y 2 =400
(20
3 -x) 2 + (30+y) 2 =2500 ,
解得
x=
20
21
7
y=
40
7
7 (负值舍去),
∴S 四边形ABCD=S △ABE+S 梯形AEFD-S △CFD=
1
2 ×20×20
3 +
1
2 (20
3 +
20
21
7 )(30+
40
7
7 )-
1
2 ×
20
21
7 ×
40
7
7
=500
3 +100
21 (m 2).
即这块菜地的面积是(500
3 +100
21 )平方米.