顶级难数学计算(代数式)1 / x-y — 1/ x+y + 2y/ x^2+y^2 — 4x^2y/x^4+y^4分式

2个回答

  • 1 /(x-y)—1/(x+y)+ 2y/(x^2+y^2)—4x^2y/(x^4+y^4)

    ={1 /(x-y)—1/(x+y)++ 2y/(x^2+y^2)—4x^2y/(x^4+y^4)

    =2y/(x^2-y^2)+ 2y/(x^2+y^2)—4x^2y/(x^4+y^4)

    ={2y/(x^2-y^2)+ 2y/(x^2+y^2)}—4x^2y/(x^4+y^4)

    =4x^2y/(x^4-y^4)-4x^2y/(x^4+y^4)

    =4x^6y/(x^8-y^8)

    这题一看似乎有些麻烦,因为直接把四项分母化成统一挺麻烦的,但是计算时可以每两项加一次然后这么算几次,每次都是把两项分母化成统一,这样少简单些