证明:因为A的秩为1,所以A的所有行都成比例,且第1行不是0行
则 A =
a11 a12 ...a1n
k2a11 k2a12 ...k2a1n
....
kna11 kna12 ...kna1n
= (1,k2,...,kn)'(a11 a12 ...a1n)
此即题目所要求的形式.
证明:因为A的秩为1,所以A的所有行都成比例,且第1行不是0行
则 A =
a11 a12 ...a1n
k2a11 k2a12 ...k2a1n
....
kna11 kna12 ...kna1n
= (1,k2,...,kn)'(a11 a12 ...a1n)
此即题目所要求的形式.