Question

已知x+y=1/2,求x^2y+xy^2的值 已知x=6,y=1/6,求x^2+xy-5x-5y的值

Answer 1

已知x+y=1/2,求x^2y+xy^2的值

少一个条件

已知x=6,y=1/6,求x^2+xy-5x-5y的值

原式=x(x+y)-5(x+y)

=(x+y)(x-5)

=(6+1/6)(6-5)

=37/6

1.825^2x3-175^2x3

=3(825²-175²)

=3(825+175)(825-175)

=3×1000×650

=1950000

2.2010^2+2012^2-4020x2012.

=2010²-2×2010×2012+2012²

=(2010-2012)²

=4