（a）不计空气阻力，从抛出点到再落回来，整个过程是对称的，所以落回的速度大小为抛出的速度的大小，只不过是方向相反，即v2=-8.0m/s
（b）因为：根据时间也对称：所以有，
t=2*(0-v1)/g=16/9.8=1.63 s 取 g=-9.8m/s^2
加拿大高中物理题A stone is thrown vertically upward with an initial
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