(1)
设甲种货车每次运货 x 吨,乙种货车每次运货 y 吨.
可列方程组:2x+3y = 20.5 ,5x+6y = 46 ,
解得:x = 5 ,y = 3.5 ,
即:甲种货车每次运货 5 吨,乙种货车每次运货 3.5 吨.
(2)
3辆甲种货车与5辆乙种货车一次运货 5×3+3.5×5 = 32.5 吨,
按每吨付运费30元计算,货主应付运费 30×32.5 = 975 元.
(1)
设甲种货车每次运货 x 吨,乙种货车每次运货 y 吨.
可列方程组:2x+3y = 20.5 ,5x+6y = 46 ,
解得:x = 5 ,y = 3.5 ,
即:甲种货车每次运货 5 吨,乙种货车每次运货 3.5 吨.
(2)
3辆甲种货车与5辆乙种货车一次运货 5×3+3.5×5 = 32.5 吨,
按每吨付运费30元计算,货主应付运费 30×32.5 = 975 元.