1 、x+y=8 xy=6 求x²+3xy+2y²/x²y+2xy²

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  • 1 、x+y=8 xy=6 求x²+3xy+2y²/x²y+2xy²的值.

    x²+3xy+2y²/x²y+2xy²

    =(x+2y)(x+y)/xy(x+2y)

    =(x+y)/xy x+y=8 xy=6

    =8/6

    =4/3

    2、3/a=4/b=5/c,求分式 ab-bc+ac/a²+b²+c²的值

    ∵3/a=4/b=5/c,

    ∴b=4a/3

    c=5a/3

    ∴ab-bc+ac/a²+b²+c²

    =(a*4a/3-4a/3*5a/3+a*5a/3)/(a²+16a²/9+25a²/9)

    =(4a²/3-20a²/9+5a²/3)/(50a²/9)

    =(27a²/9-20a²/9)/(50a²/9)

    =(7a²/9)/(50a²/9)

    =7/50