Question

已知x 根号3+1 求根号x的平方分子1+2x+x平方

Answer 1

因为x=√3+1 所以x﹥0,x-1﹥0 原式=√[x/(1-2x+x)] =√[x/(x-1)] =x/(x-1) =(√3+1)/(√3+1-1) =(√3+1)/(√3) =[(√3+1)×√3]/(√3×√3) =(3+√3)/3