令√2x^2+3x-2=t>=0
原方程变为
3t^2+t=0
t=0或t=-1/3(舍去)
所以
2x^2+3x-2=0
(2x-1)(x+2)=0
x1=-2,x2=1/2
6x^2+9x+根号2x^2+3x-2=6
3个回答
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