2003÷2003又2003/2004+1/2005
＝2003÷（2003×2004＋2003）/2004+1/2005
＝2003÷[2003×（2004＋1）]/2004+1/2005
＝2003÷（2003×2005）/2004+1/2005
＝2003×2004/（2003×2005）+1/2005
＝2004/2005+1/2005
＝1
1995×(1/6-1/2001)+6×(1/1995-1/2001)-2001×(1/1995+1/6)+6
=1995×(1/6-1/2001)+6×(1/1995-1/2001)-(1995+6)×(1/1995+1/6)+6
=1995×(1/6-1/2001)+6×(1/1995-1/2001)-1995×(1/1995+1/6)-6×(1/1995+1/6)+6
=1995×(1/6-1/2001)+6×(1/1995-1/2001)-1-1995/6-6/1995-1+6
=1995×(1/6-1/2001)+6×(1/1995-1/2001)-1995/6-6/1995+4
=1995/6-1995/2001+6/1995-6/2001-1995/6-6/1995+4
=-1995/2001+6/1995-6/2001-6/1995+4
=-1995/2001-6/2001+6/2001-6/1995+4
=4-1
=3