x³-3xy-y³
=x³-y³-3xy
=（x-y）（x²+xy+y²）-3xy
=x²+xy+y²-3xy
=x²-2xy+y²
=（x-y）²
=1
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x-y=1求证x³-3xy-y³=1
x³-3xy-y³
=x³-y³-3xy
=（x-y）（x²+xy+y²）-3xy
=x²+xy+y²-3xy
=x²-2xy+y²
=（x-y）²
=1
很高兴为您解答,【the1900】团队为您答题.
请点击下面的【选为满意回答】按钮,