1.若COS2a/sin(a-兀/4)=-(根号2)/2.则COSa+sina=?

2个回答

  • 1,cos2a=cosacosa-sinasina=(cosa+sina)(cosa-sina)

    sin(a-兀/4)=sinacos兀/4-cosasin兀/4=(根号2)/2(sina-cosa)

    cos2a/sin(a-兀/4)=-(根号2)(cosa+sina)=-(根号2)/2(已知)

    cosa+sina=1/2

    2,根据正弦定理a/sinA=b/sinB

    由a=2bsinA可知:a/sinA=b/(1/2)

    所以sinB=1/2,因为三角形ABC是锐角三角形,所以B=30度

    cosA=sin(90-A)=sin[90-(180-B-C)]=sin(C-60)

    cosA+sinC=sin(C-60)+sinC=2sin[(C-60+C)/2]cos[(C-60-C)/2]=2sin(C-30)cos30=根号3*sin(C-30)

    因为B=30,所以60