lim(x→π)[(sin3x)/(x-π)],用洛必达法则
=lim(x→π)[3cos3x]
=3cos(3π)
=3*(-1)
=-3
lim(x→π/2)[(1+cosx)^(secx)]
=lim(x→π/2)[(1+cosx)^(1/cosx)],用y=1/cosx
=lim(y→∞)[(1+1/y)^y]
=e
lim(x→π)[(sin3x)/(x-π)],用洛必达法则
=lim(x→π)[3cos3x]
=3cos(3π)
=3*(-1)
=-3
lim(x→π/2)[(1+cosx)^(secx)]
=lim(x→π/2)[(1+cosx)^(1/cosx)],用y=1/cosx
=lim(y→∞)[(1+1/y)^y]
=e