Question

如图,在三角形ABC中∠ACB=90°,AD平分∠BAC,DE⊥AB于E求证；直线AD是CE的垂直平分线求大神帮助

Answer 1

证明：∵DE⊥AB,∴∠AED=90°=∠ACB,又∵AD平分∠BAC,∴∠DAE=∠DAC,∵AD=AD,∴△AED≌△ACD,∴AE=AC,∵AD平分∠BAC,∴AD⊥CE,即直线AD是线段CE的垂直平分线