Question

已知一次函数为Y=（A-2）X+3A的2次方-12,求

Answer 1

1.

y=(A-2)x+3A^2-12

0=0+3A^2-12

A^2=4

A=2或-2

2.

y=(A-2)x+3A^2-12

-9=0+3A^2-12

A^2=1

A=1或-1