Question

f(x)=sinx+2xf'(π/3) f(π/3)=f(-π/3)大小关系

Answer 1

f(x)=sinx+2xf'(π/3),则：

f'(x)=cosx+2f'(π/3),

所以

f'(π/3)=cosπ/3+2f'(π/3),

f'(π/3)=-cosπ/3=-1/2,

所以 f(x)=sinx-x,

而f(π/3)=sinπ/3-π/3=√3/2-π/30,

所以f(π/3)