∫x/√[(x²+3)^n]dx (2→+∞)
=½∫1/[(x²+3)^(n/2)]dx² (2→+∞)
=½∫[(x²+3)^(-n/2)]d(x²+3) (2→+∞)
=[1/(2-n)](x²+3)/(x²+3)^(n/2)] (2→+∞)
当 n>2,(x²+3)^(n/2)>(x²+3),结果收敛.
∫x/√[(x²+3)^n]dx (2→+∞)
=½∫1/[(x²+3)^(n/2)]dx² (2→+∞)
=½∫[(x²+3)^(-n/2)]d(x²+3) (2→+∞)
=[1/(2-n)](x²+3)/(x²+3)^(n/2)] (2→+∞)
当 n>2,(x²+3)^(n/2)>(x²+3),结果收敛.