x2+xy-2y2=0
(x-y)(x+2y)=0
x-y=0,x+2y=0
x=y或x=-2y
x=y,则原式=(y2+3y2+y2)/(y2+y2)=5y2/2y2=5/2
x=-2y,则原式=(4y2-6y2+y2)/(4y2+y2)=-y2/5y2=-1/5
若x2+xy-2y2=0,则(x2+3xy+y2)／(x2+y2)=?
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