(sinx+siny)^2+(cosx+cosy)^2为什么等于1+1+2(sinxsiny+cosxcosy)=2+2

2个回答

  • (sinx+siny)^2+(cosx+cosy)^2

    = sinx^2 + siny^2 + 2sinxsiny + cosx^2 + cosy^2 + 2cosxcosy

    =(sinx^2 + cosx^2)+(siny^2 + cosy^2)+ 2sinxsiny + 2cosxcosy

    = 1 + 1 + 2 (sinxsiny + cosxcosy)

    再根据 余弦差交公式 sinxsiny+cosxcosy = cos(x-y)

    即得 (sinx+siny)^2+(cosx+cosy)^2

    = 1 + 1 + 2 (sinxsiny + cosxcosy)

    = 2 + 2cos(x-y)