Question

（3）（m的平方-9分之12）+（3-m分之2）+（m+3分之2）

Answer 1

12/(m^2-9)+2/(3-m)+2/(m+3)

=12/(m^2-9)-2/(m-3)+2/(m+3)

=12/[(m-3)(m+3)]-2(m+3)/[(m-3)(m+3)]+2(m-3)/[(m-3)(m+3)]

=[12-2(m+3)+2(m-3)]/[(m-3)(m+3)]

=[12-2m-6+2m-6]/[(m-3)(m+3)]

=0/[(m-3)(m+3)]

=0