Question

例如这样：y=4x²+3x+1y＇=（4x²+3x+1）＇=（4x²）＇+（3x）+1＇=4（x²）＇+3x＇+1＇=4

Answer 1

y=x+lnx+1

y'=1+1/x

y=2cosx+3x

y'=-2sinx+3

y=(9x+3)ˆ5

y'=5(9x+3)^4*9=45*81(3x+1)^4

y=e^2x+3

y'=2e^(2x)

y=sin(8x+1)

y'=8cos(8x+1)