化简:(x²-2x分之x+2再减去x²-4x+4分之x-1)÷x分之4-x

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  • 你的表达有问题啊!请注意括号的正确使用,以免造成误解.

    [(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)]÷[(4-x)/x]

    ={(x+2)/[x(x-2)]-(x-1)/(x-2)^2}[x/(4-x)]

    ={(x+2)(x-2)/[x(x-2)^2]-x(x-1)/[x(x-2)^2]}[x/(4-x)]

    ={[(x^2-4)-(x^2-x)]/(x-2)^2}/(4-x)

    =(x^2-4-x^2+x)/[(4-x)(x-2)^2]

    =-(4-x)/[(4-x)(x-2)^2]

    =-1/(x-2)^2.