1) cosα =-4/5,且α为第三象限角
==>sinα=-3/5
sin(α+π/3)=sinα*(1/2)+cosα *(√3/2)
=-3/5*(1/2)+(-4/5)*(√3/2)=(3-4√3)/10
2) [2sin(π/4+α)sin(π/4-α)]/sin(π-2α)
=2sin(π/4+α)cos(π/4+α)/sin(2α)
=sin2(π/4+α)/sin(2α)=sin(π/2+2α)/(sin2α)
=cos2α/sin2α
cosα =-4/5,sinα=-3/5==>sin2α=2*(-3/5)*(-4/5)=24/25
cos2α=2cos²α-1=2*(16/25)-1=7/25
[2sin(π/4+α)sin(π/4-α)]/sin(π-2α)=cos2α/sin2α=7/24