Question

[(lg2+lg5-lg1)/(2lg0.5+lg8)]*(lg32-lg2) 分步计算步骤,

Answer 1

[(lg2+lg5-lg1)/(2lg0.5+lg8)]*(lg32-lg2)

=[(lg2*5/1)/(lg0.5*0.5*8)]*lg32/2

=(1/lg2)*lg16

=4lg2/lg2

=4