Question

求证logaM/N=logaM-logaN

Answer 1

设a＾x=M,a＾y=N

M/N=(a＾x)/(a＾y)=a＾(x-y)

loga (M/N)=loga a＾(x-y)=x-y

loga M-loga N=x-y

所以loga (M/N)=loga M-loga N