Question

通分(2x-4)平方分之x,6x-3x平方分之一,x平方-4分之2x

Answer 1

x/(2x-4)^2=x/4(x-2)^2=[x*3x(x+2)]/[4(x-2)^2*3x(x+2)]=[3x^2(x+2)]/[12x(x+2)(x-2)^2]1/(6x-3x^2)=-1/[3x(x-2)]=-[4(x-2)(x+2)]/[3x(x-2)*4(x-2)(x+2)]=-[4(x-2)(x+2)]/[12x(x+2)(x-2)^2]2x/(x^2-4)=2x/[(x-2)(x+2...