2/(x-1) - 3/(x+1) = 1
因为最小公倍数为(x+1)*(x-1)
所以方程两边同乘(x+1)*(x-1)
则 2(x+1)-3(x-1)=(x+1)*(x-1)
化简2x+2-3x+3=x²-1即x²+x-6=0
化简(x+3)*(x-2)=0
所以x=2或x=-3
2/(x-1) - 3/(x+1) = 1
因为最小公倍数为(x+1)*(x-1)
所以方程两边同乘(x+1)*(x-1)
则 2(x+1)-3(x-1)=(x+1)*(x-1)
化简2x+2-3x+3=x²-1即x²+x-6=0
化简(x+3)*(x-2)=0
所以x=2或x=-3