解一元二次方程共有三种方式,:配方法、公式法、因式分解法,用其中一种解!

1个回答

  • 1 .196x^2-1=0

    (14x+1)(14x-1)=0 x1=-1/14 x2=1/14

    2.4x^2+12x+9=81

    x^2+3x-18=0 (x+6)(x-3)=0 x1=-6 x2=3

    3.x^2-7x-1=0

    x=[7±根号(49+4)]/2 x1=(7+根号53)/2 x2=(7-根号53)/2

    4.2x^2+3x=3

    2x^2+3x-3=0 x=[-3±根号(9+24)]/4 x1=(-3+根号33)/4 x2=(-3-根号33)/4

    5.x^2-2x+1=25

    x^2-2x-24=0 (x-6)(x+4)=0 x1=6 x2=-4

    6 .x(2x-5)=4x-10

    2 x^2-9x+10=0 x=[9±根号(81-80)]/4 x=(9±1)/4 x1=5/2 x2=2

    7.x^2+5x+7=3x+11

    x^2+2x-4=0 (x+1)^2=5 x+1=±根号5 x1=-1+根号5 x2=-1-根号5

    8.1-8x+16x^2=2-8x

    16x^2-1=0 (4x+1)(4x-1)=0 x1=-1/4 x2=1/4