Question

在等边△ABC中,点D.E分别在BC、AB上,且BD=AE,AD与CE交与点F.求∠DFE的度数

Answer 1

在△ABD和△CAE中,

AB = CA ,∠ABD = 60°= ∠CAE ,BD = AE ,

所以,△ABD ≌ △CAE ,

可得：∠BAD = ∠ACE ,

∠DFE = ∠AEF+∠BAD = (∠ABC+∠BCE)+∠ACE = ∠ABC+∠ACB = 120°.

应该是求∠DFC的度数吧（∠DEC求不出的）,

∠DFC = ∠CAD+∠ACE = ∠CAD+∠BAD = ∠BAC = 60°.