5a²+[a²+(5a²-3a²)-6(a²-a) - 知识问答

5a²+[a²+(5a²-3a²)-6(a²-a)],其中a=负二分之

1个回答

5a²+[a²+(5a²-3a²)-6(a²-a)],
=5a²+(a²+2a²-6a²+6a)
=5a²+a²+2a²-6a²+6a
=2a²+6a
=2*1/4+6*(-1/4)
=1/2-3/2
=-1

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