因式分解【急死了,1.x²-4xy+4y²-10x+20y+252.(n+1)(n+2)(n+3)(

6个回答

  • 1.x²-4xy+4y²-10x+20y+25

    =(x^2-4xy+4y^2)-(10x-20y)+25

    =(x-2y)^2-10(x-2y)+25

    =(x-2y-5)^2

    2.(n+1)(n+2)(n+3)(n+4)+1

    =[(n+1)(n+4)][(n+2)(n+3)]+1

    =(n^2+5n+4)(n^2+5n+6)+1

    =(n^2+5n)^2+10(n^2+5n)+24+1

    =(n^2+5n)^2+10(n^2+5n)+25

    =(n^2+5n+5)^2

    填空题

    当x=_______时,代数式x²-4x+10有最小值,最小值是_______

    x^2-4x+10=(x^2-4x+4)+6

    =(x-2)^2+6

    因为(x-2)^2≥0

    所以当(x-2)^2=0时,即x=2时,代数式x²-4x+10有最小值,最小值是6