Question

求积分 ∫1到8 [(x^1/3+1)(2-x^2/3)]/x^1/3 dx

Answer 1

=∫[x^(1/3)-x+2-x^(2/3)]/x^(1/3)]dx

=∫[1-x^(2/3)+2x^(-1/3)-x^(1/3)]]dx

幂函数积分

=x-x^(5/3)/(5/3)+2x^(2/3)/(2/3)-x^(4/3)/(4/3)(1,8)

代入算一下吧